本文實例為大家分享了C++實現俄羅斯方塊的具體代碼，供大家參考，具體內容如下
工具：vc++2010,圖庫:EasyX
先看效果圖片
純手寫，沒有面向對象思想,看全部源碼
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#include <stdio.h>#include <graphics.h>#include <time.h>#include <conio.h>#define BLOCK_COUNT 5#define BLOCK_WIDTH 5#define BLOCK_HEIGHT 5#define UNIT_SIZE 20#define START_X 130#define START_Y 30#define KEY_UP 72#define KEY_RIGHT 77#define KEY_LEFT 75#define KEY_SPACE 32#define KEY_DOWN 76typedef enum{ BLOCK_UP, BLOCK_RIGHT, BLOCK_DOWN, BLOCK_LEFT}block_dir_t;typedef enum{ MOVE_DOWN, MOVE_LEFT, MOVE_RIGHT}move_dir_t;int speed = 500;int NextIndex = -1;//下一個方塊種類int BlockIndex = -1;//當前方塊種類int score = 0;//分數int rank = 0;//等級int visit[30][15];//訪問數組int markcolor[30][15];//表示顏色int minX = 30;int minY = 30;int color[BLOCK_COUNT]={ GREEN,CYAN,MAGENTA,BROWN,YELLOW};int block[BLOCK_COUNT*4][BLOCK_HEIGHT][BLOCK_WIDTH] = { //條形方塊 { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,0,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,0,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, //L形方塊 { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,1,1,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,0,0, 0,1,1,1,0, 0,1,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, //田字型 { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, //T字形方塊 { 0,0,0,0,0, 0,1,1,1,0, 0,0,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,0,1,1,0, 0,0,0,1,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,1,0,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,1,0, 0,0,1,0,0, 0,0,0,0,0}, //Z字形方塊 { 0,0,0,0,0, 0,1,1,0,0, 0,0,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,0,1,1,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,0,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,0,1,1,0, 0,0,1,0,0, 0,0,0,0,0}};//歡迎界面void welcome(){ //初始化畫布 initgraph(550,660); //設置窗口標題 HWND window = GetHWnd();//獲取窗口 SetWindowText(window,_T("俄羅斯方塊 GWF"));//設置窗口標題 //設置文本字體樣式 setfont(0,30,_T("微軟雅黑")); setcolor(YELLOW); outtextxy(150,200,_T("俄羅斯方塊")); setfont(0,10,_T("微軟雅黑")); outtextxy(175,300,_T("IT編程從俄羅斯方塊開始")); Sleep(3000); }//初始化游戲屏幕void initGameScene(){ char str[16]; //清除屏幕 cleardevice(); rectangle(27,27,336,635); rectangle(29,29,334,633); rectangle(370,50,515,195); setfont(24,0,_T("楷體")); setcolor(LIGHTGRAY); outtextxy(405,215,_T("下一個")); setcolor(RED); outtextxy(405,280,_T("分數")); sprintf(str,"%d",score); outtextxy(415,310,str); outtextxy(405,375,_T("等級")); sprintf(str,"%d",rank); outtextxy(415,405,str); setcolor(LIGHTBLUE); outtextxy(390,475,"操作說明"); outtextxy(390,500,"↑:旋轉"); outtextxy(390,525,"↓:下降"); outtextxy(390,550,"→:向右"); outtextxy(390,575,"←:向左"); outtextxy(390,600,"空格:暫停");}void drawBlock(int x,int y){//右上角畫出方塊 setcolor(color[NextIndex]); setfont(23,0,"楷體"); for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ if(block[NextIndex*4][i][j] == 1){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } } }}void drawBlock(int x,int y,int blockIndex,block_dir_t dir){//按索引畫出什么方塊指定位置方塊指定方向 setcolor(color[blockIndex]); setfont(23,0,"楷體"); int id = blockIndex*4+dir; for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ if(block[id][i][j] == 1){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } } }}void clearBlock(int x, int y){ setcolor(BLACK); setfont(23,0,"楷體"); for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } }}void clearBlock(int x, int y,block_dir_t dir){ setcolor(BLACK); int id = BlockIndex *4+dir; y+=START_Y; for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ if(block[id][i][j] == 1){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } } }}void nextblock(){ clearBlock(391,71);//清除右上角方塊 //隨機選擇一種方塊 srand(time(NULL));//時間函數的返回值產生隨機數種子 NextIndex = rand()%BLOCK_COUNT; drawBlock(391,71);//畫出方塊}//如果在指定位置可以向方向移動int moveable(int x0,int y0,move_dir_t moveDir,block_dir_t blockDir){ int x = (y0 - minY)/UNIT_SIZE; int y = (x0 - minX)/UNIT_SIZE; int id = BlockIndex * 4+blockDir; int ret = 1; if(moveDir == MOVE_DOWN){ for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] == 1 &&(x+i+1>=30 || visit[x+i+1][y+j]==1)){ ret=0; } } } }else if(moveDir == MOVE_LEFT){ for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] == 1 &&(y+j==0 || visit[x+i][y+j-1]==1)){ ret=0; } } } }else if(moveDir == MOVE_RIGHT){ for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] == 1 &&(y+j+1>=15 || visit[x+i][y+j+1]==1)){ ret=0; } } } } return ret;}void failCheck(){//游戲是否結束 if(!moveable(START_X,START_Y,MOVE_DOWN,BLOCK_UP)){ setcolor(WHITE); setfont(45,0,"隸體"); outtextxy(75,300,"GAME OVER!"); Sleep(1000); system("pause"); closegraph(); exit(0); }}int wait(int interval){//等待 int count = interval/5; for(int i = 0;i<count;i++){ Sleep(5); if(kbhit()){ return 0; } }}//判斷當前方向是否可以轉到指定方向int rotatable(int x,int y,block_dir_t dir){ int id= BlockIndex * 4 +dir; int xIndex = (y-minY)/20; int yIndex = (x-minX)/20; if(!moveable(x,y,MOVE_DOWN,dir)){ return 0 ; } for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] ==1&&(yIndex+j<0||yIndex+j>=15||visit[xIndex+i][yIndex+j] ==1)){ return 0 ; } } } return 1;}void mark(int x,int y,int blockIndex,block_dir_t dir){ int id = blockIndex*4+dir; int x2 = (y-minY)/20; int y2 = (x-minX)/20; for(int i=0;i<5;i++){ for(int j=0;j<5;j++){ if(block[id][i][j] ==1){ visit[x2+i][y2+j]=1; markcolor[x2+i][y2+j]=color[blockIndex]; } } }}void clear_down(int x){//消除第x行,并把上面的行都下移 for(int i = x;i>0;i--){ for(int j=0;j<15;j++){ if(visit[i-1][j]){//上面有東西 visit[i][j]=1; markcolor[i][j]=markcolor[i-1][j]; setcolor(markcolor[i][j]); outtextxy(20*j+minX,20*i+minY,"■"); }else{ visit[i][j] =0; setcolor(BLACK); outtextxy(20*j+minX,20*i+minY,"■"); } } } //清除最頂層那一行,就是行標位0的哪一行 setcolor(BLACK); for(int j = 0;j<15;j++){ visit[0][j] = 0; outtextxy(20*j+minX,minY,"■"); }}void updataGrade(){//更新等級提示//假設:50分一級 char str[10]; rank = score/50; sprintf(str,"%d",rank); outtextxy(425,405,str); //更新速度,等級越高速度越快,speed越小 //最慢是500,最快是50 speed = 500-rank*50; if(speed<=0){ speed = 50; }}void addScore(int lines){//更新分數,line表示消除的行數 char str[32]; setcolor(RED); score+=lines*10; sprintf(str,"%d",score); outtextxy(415,310,str);}void check(){//消去方塊 int i,j; int clearLines =0; for(i=29;i>=0;i--){ for(j=0;j<15 && visit[i][j];j++); //執行到此處有兩種情況, //1.第I行沒有滿,即表示有空位,此時j<15 //2.第i行已經滿了,j就大于等于15 if(j>=15){ //此時第i行已經滿了,就需要消除第i行 clear_down(i);//清除第i行,并把上面的行都下移動 i++; clearLines++; } } //更新分數 addScore(clearLines); //更新等級 updataGrade();}void move(){ int x = START_X; int y = START_Y; int k = 0; int curSpeed = speed; block_dir_t blockDir = BLOCK_UP; //檢查游戲是否結束 failCheck(); while(1){ if(kbhit()){ int key = getch(); if(KEY_SPACE == key){ getch(); } } //清除當前方塊 clearBlock(x,k,blockDir); if(kbhit()){ int key = getch(); if(KEY_UP == key){//變形 block_dir_t nextDir = (block_dir_t)((blockDir+1)%4); if(rotatable(x,y+k,nextDir)){ blockDir= nextDir; } }else if(KEY_DOWN == key){//鄉下加速 curSpeed = 50; }else if(KEY_RIGHT == key){//右移動 if(moveable(x,y+k+20,MOVE_RIGHT,blockDir)){ x+=20; } }else if(KEY_LEFT == key){//左移動 if(moveable(x,y+k+20,MOVE_LEFT,blockDir)){ x-=20; } } } k+=20; //繪制當前方塊 drawBlock(x,y+k,BlockIndex,blockDir); wait(curSpeed); //方塊降落到底層的固化處理 if(!moveable(x,y+k,MOVE_DOWN,blockDir)){ mark(x,y+k,BlockIndex,blockDir); break; } }}void newblock(){ //確定即將使用的方塊 BlockIndex = NextIndex; //繪制方塊從頂部掉下來 drawBlock(START_X,START_Y); //新出現的方塊等一下 Sleep(100); //右上角繪制下一個方塊 nextblock(); //向下降落的動作 move();}int main (void){ welcome(); initGameScene(); //產生新方塊 nextblock(); Sleep(500); memset(visit,0,sizeof(visit)); while(1){ newblock(); //消除滿行,并更新分數和速度 check(); } system("pause"); closegraph(); return 0;} |
分析項目：
1.必須要有歡迎界面
2.搭建合理的邊界,就是游戲范圍
3.邏輯1:先出現右上方的方塊樣式,等待一段時間,將右上方的樣式在游戲區打印出
4.邏輯2,方塊降落,要擦除原先印記,將1改為0
5.邏輯3,熱鍵控制移動方向,暫停及變形,且不能移動出界,判斷方塊是否還能移動
6.邏輯4,方塊凝固在下方不出界
7.邏輯5,最下面一行方塊疊滿了,消去它并把上面的行都下移(分兩種情況),并且再次檢查這一行
8.邏輯6,計算消除行數次數,統計分數,控制休眠時間長度
9.邏輯7,每次移動先判斷是否能移動,默認結束程序,在合理游戲區返回false,結束界面
總結：從界面開始到完整的架構,功能后實現,一步一步,邏輯嚴謹,思路清晰,注釋在代碼里。
以上就是本文的全部內容，希望對大家的學習有所幫助，也希望大家多多支持服務器之家。
原文鏈接：https://blog.csdn.net/acararduino/article/details/103947960
